The speeds of trains A ( S a S_a S a ​ ) and B ( S b S_b S b ​ ) in km/hr, with S a > S b S_a > S_b S a ​ > S b ​ , are the roots of the equa...

Question

The speeds of trains A (SaS_a) and B (SbS_b) in km/hr, with Sa>SbS_a > S_b, are the roots of the equation:

x2130x+4200=0x^2 - 130x + 4200 = 0

Let TaT_a and TbT_b be the usual times (in hours) taken by trains A and B respectively to cover a distance DD km. If their speeds are interchanged for the same distance DD (i.e., train A travels at speed SbS_b and train B at speed SaS_a), then train A takes (Ta+2)(T_a + 2) hours and train B takes (Tb2)(T_b - 2) hours.

Find the sum of the original times Ta+TbT_a + T_b.

Options

A.

22

B.

21

C.

25

D.

24

E.

26

quadratic equationspeed and timealgebratrain problems

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