There are three bags A, B and C. In each bag there are three types of colored balls Yellow, Green and Black. In bag A, no. of yellow colored balls are...

Question

There are three bags A, B and C. In each bag there are three types of colored balls Yellow, Green and Black. In bag A, no. of yellow colored balls are y and no. of green colored balls are g. Number of green colored balls are 4 more than the number of yellow colored balls. When one ball is picked at random then the probability of getting black color ball is 5 13 . The value of y is 18 2 11 % less then g. In bag B, number of yellow colored balls is 22 2 9 % more than that of bag A. If two balls are picked at random from bag B then the probability of getting both green color ball is 4 37 . Total number of balls in bag B is 75. In bag C, the ratio of number of green colored balls and number of black colored balls is 7 : 5. Total number of green and black colored balls is 36. If one ball is picked at random then the probability of getting one yellow ball is 7 13 .
If x yellow balls are transferred from bag B to bag A, and 20% of black balls from bag A are moved to bag B, then the probability of drawing a black ball from bag B becomes 1126\frac{11}{26}. Find the value of x.

Options

A.

5

B.

6

C.

3

D.

2

probabilityratiopercentagebag problemmultiple step reasoning

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