Two rhombuses PQRS and MLKJ have sides calculated as follows: Side of rhombus PQRS is calculated using the formula 6 2 + 8 2 = 10 = 5 cm \sqrt{\frac{6...

Question

Two rhombuses PQRS and MLKJ have sides calculated as follows:

  • Side of rhombus PQRS is calculated using the formula 62+82=10=5 cm\sqrt{\frac{6}{2} + \frac{8}{2}} = \sqrt{10} = 5 \text{ cm}.
  • For rhombus MLKJ, given sin30=perpendicularhypotenuse=12=7.5side of MLKJ\sin 30^\circ = \frac{\text{perpendicular}}{\text{hypotenuse}} = \frac{1}{2} = \frac{7.5}{\text{side of MLKJ}}, the side of MLKJ is found to be 15 cm15 \text{ cm}.

If AB is the side of PQRS and CD is the side of MLKJ, what is the length of the median XY of trapezium ABCD formed by these sides?

Screenshot 2025-09-03 01.54.55.png

Calculate the median XY using the formula:

XY=AB+CD2XY = \frac{AB + CD}{2}

Options

A.

7.5 cm7.5 \text{ cm}

B.

10 cm10 \text{ cm}

C.

12.5 cm12.5 \text{ cm}

D.

20 cm20 \text{ cm}

geometryrhombusmediantrapeziumtrigonometry

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